Baltic Olympiad in Informatics 2001 - tasks and solutions by M.Kubica, V.Leppanen, A.Malinowski, O.Murk, K.Onak,

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By M.Kubica, V.Leppanen, A.Malinowski, O.Murk, K.Onak, M.Opmanis, M.Plukas, W.Pohl, A.Truu, P.Sankowski, M.Sawicki, M.Stefaniak, T.Walen, P.Wolf

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In this case capacitors C1 and C2 are discharged via the circuit S2–V2–S4–C1–S7–C2, and the voltage across capacitor C1 and C2 is decreasing. Capacitors C1 and C2 transfer the energy from the source to the load. 6c. 7. Since V1 > V2 two capacitors C1 and C2 are in parallel during switch-on and in series during switch-off. The voltage lift technique is applied. During switchon state, switches S2, S4, S6, and S8 are closed. 6 Mode A2 (quadrant I) forward motoring operation with V1 < V2. capacitors C1 and C2 is increasing.

3a and b. Actually, the variations of currents iL1 and iL2 are small so that iL1 ª IL1 and iL2 ª IL2 The charge on capacitor C increases during switch off and on: Q+ = (1 – k)T IL2 Q– = kTIL1 In a whole period investigation, Q+ = Q–. 15) Since capacitor C performs as a low-pass filter, the output current IL2 = I2 The source current i1 = iL1 + iL2 during switch-on, and i1 = 0 during switchoff. 26) The free-wheeling diode’s current iD1 during switch off is: iD1 = iL1 + iL2. Its peak-to-peak variation is DiD 2 = DiL1 + DiL 2 = V2 - VS - RI 2 kT L where L = L1L2 /( L1+ L2).

2b: switches S2, S3, and S4 are closed and diodes D8, D9, and D9 are conducted. Other switches and diodes are open. In this case capacitor C1 (C2 and C3) is discharged via the circuit S2(S3 and S4)–VL–D8(D9 and D10)–C1(C2 and C3), and the voltage across capacitor C1 (C2 and C3) is decreasing. 5 V. Capacitors C1, C2, and C3 transfer the energy from the source to the load. 2c. Mode A uses the current-amplification technique. All three capacitors are charged in series during state-on. The input current flows through three capacitors and the charges accumulated on the three capacitors should be the same.

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